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Answer :
x - the first integer
x+2 - the second integer
x+4 - the third integer
[tex]x+x+2+x+4=141 \\
3x+6=141 \\
3x=141-6 \\
3x=135 \\
x=\frac{135}{3} \\
x=45 \\ \\
x+2=45+2=47 \\
x+4=45+4=49[/tex]
The integers are: 45, 47, 49.
x+2 - the second integer
x+4 - the third integer
[tex]x+x+2+x+4=141 \\
3x+6=141 \\
3x=141-6 \\
3x=135 \\
x=\frac{135}{3} \\
x=45 \\ \\
x+2=45+2=47 \\
x+4=45+4=49[/tex]
The integers are: 45, 47, 49.
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