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Slowpoke Sally drags a couch for 5 meters in 2 minutes. If she pulls with a force of 3000 N, what power was outputted?

Answer :

Sure, I'd be happy to help!

Let's break down the problem and solve it step by step.

1. Understanding the Given Information:
- Distance dragged: [tex]\(5\)[/tex] meters
- Time taken: [tex]\(2\)[/tex] minutes
- Force applied: [tex]\(3000\)[/tex] Newtons

2. Convert Time to Seconds:
Since power calculations require time in seconds, we need to convert the given time from minutes to seconds.
[tex]\[
2 \text{ minutes} = 2 \times 60 \text{ seconds} = 120 \text{ seconds}
\][/tex]

3. Calculate the Work Done:
Work done ([tex]\(W\)[/tex]) can be calculated using the formula:
[tex]\[
W = \text{Force} \times \text{Distance}
\][/tex]
Substituting the given values:
[tex]\[
W = 3000 \text{ N} \times 5 \text{ m} = 15000 \text{ Joules}
\][/tex]

4. Calculate the Power Output:
Power ([tex]\(P\)[/tex]) can be calculated using the formula:
[tex]\[
P = \frac{\text{Work Done}}{\text{Time}}
\][/tex]
Substituting the previously calculated work done and the converted time:
[tex]\[
P = \frac{15000 \text{ Joules}}{120 \text{ seconds}} = 125 \text{ Watts}
\][/tex]

So, the power outputted by Sally is [tex]\(125 \text{ Watts}\)[/tex].

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Rewritten by : Barada