We appreciate your visit to Exponential Growth and Decay Word Problem If the number of bacteria in a colony doubles every 203 minutes and there is currently a population of. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Final answer:
The population of bacteria will be 640 after 812 minutes.
Explanation:
To find the population after 812 minutes, we can use the formula for exponential growth:
P = P0 * (2^(t/d))
Where:
- P is the final population
- P0 is the initial population
- t is the time elapsed
- d is the doubling time
In this case, the initial population (P0) is 40 bacteria, the time elapsed (t) is 812 minutes, and the doubling time (d) is 203 minutes.
Substituting these values into the formula:
P = 40 * (2^(812/203))
Calculating the exponent:
P = 40 * (2^4)
P = 40 * 16
P = 640
Therefore, the population will be 640 bacteria 812 minutes from now.
Learn more about exponential growth and decay: word problems here:
https://brainly.com/question/28142560
#SPJ14
Thanks for taking the time to read Exponential Growth and Decay Word Problem If the number of bacteria in a colony doubles every 203 minutes and there is currently a population of. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
Final answer:
The population of bacteria will be 640 after 812 minutes.
Explanation:
To find the population after 812 minutes, we can use the formula for exponential growth:
P = P0 * (2^(t/d))
Where:
- P is the final population
- P0 is the initial population
- t is the time elapsed
- d is the doubling time
In this case, the initial population (P0) is 40 bacteria, the time elapsed (t) is 812 minutes, and the doubling time (d) is 203 minutes.
Substituting these values into the formula:
P = 40 * (2^(812/203))
Calculating the exponent:
P = 40 * (2^4)
P = 40 * 16
P = 640
Therefore, the population will be 640 bacteria 812 minutes from now.
Learn more about exponential growth and decay: word problems here:
https://brainly.com/question/28142560
#SPJ14
