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In order to find the magnitude of the vectors given, let's find first the components
The component in the x-axis
[tex]C_X=5\cos (0)+6\cos (180+30)[/tex][tex]C_X=-0.196[/tex]then the component in the y-axis
[tex]C_Y=5\sin (0)+6\sin (180+30)=-3[/tex]Then the magnitude can be calculated with the next formula
[tex]|M|=\sqrt[]{Cx^2+C_Y^2}[/tex]we substitute the values
[tex]|M|=\sqrt[]{(-0.196)^2+(-3)^2}=3.01m[/tex]The magnitude is 3.01m
then for the direction, we can use the next formula
[tex]\theta=\tan ^{-1}(\frac{C_Y}{C_x})[/tex]we substitute the values
[tex]\theta=\tan ^{-1}(\frac{-3}{-0.196})=86.26\text{\degree}[/tex]then because both components are negative the direction will be
[tex]\text{direction}=86.26+180=266.26\text{\degree}[/tex]Thanks for taking the time to read Find the magnitude of the sumof these two vectors 5 60 m A 30 0 B 6 00 mmagnitude m. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
Rewritten by : Barada
