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How many moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 99.1 moles of water vapor?

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Answer :

198.2 moles of hydrogen gas are needed to react with excess carbon dioxide to produce 99.1 moles of water vapor.

The balanced equation for the reaction of hydrogen gas (H2) with carbon dioxide to produce water vapor and carbon monoxideWe have 99.1 moles of water vapor, so we need to determine how many moles of hydrogen gas are required to produce that amount of water vapor. To do this, we will use stoichiometry, which is the calculation of reactants and products in chemical reactions based on their balanced equation.

The stoichiometry for the given reaction tells us that for every 2 moles of hydrogen gas that react, 1 mole of water vapor is produced. Therefore, we can set up a ratio of moles of water to moles of H2:1 mol water : 2 mol hydrogen gas

This ratio tells us that for every 1 mole of water vapor produced, 2 moles of hydrogen gas are needed.Now, we can use this ratio to calculate how many moles of hydrogen gas are needed to produce 99.1 moles of water vapor:99.1 mol H x (2 mol hydrogen gas / 1 mol water) = 198.2 mol hydrogen gas

Therefore, 198.2 moles of hydrogen gas are needed to react with excess carbon dioxide to produce 99.1 moles of water vapor.

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