Answer :

Final answer:

All options given (a) 13, (b) 39, (c) 52, and (d) 197 are factors of the number n = 2^s x 39 x 52 x 197, hence they are all correct.

Explanation:

The question asks us to determine which of the given options are factors of the number n = 2s x 39 x 52 x 197. A factor is a number that divides into another number without leaving a remainder. To identify the factors of n, we should examine its prime factorization. In this problem, the numbers 39, 52, and 197 are already provided as factors, and 2s indicates that 2 is also a factor raised to some power s.

Breaking down the factors:

  • 39 can be factored into 3 and 13.
  • 52 can be factored into 4 (which is 22) and 13.
  • 197 is a prime number and cannot be factored further.

Given these factorizations, we can see that:

  1. 13 is a factor of both 39 and 52, so it is a factor of n.
  2. 39 is explicitly given as a factor of n.
  3. 52 is explicitly given as a factor of n.
  4. 197 is explicitly given as a factor of n.

Therefore, all options given (a) 13, (b) 39, (c) 52, and (d) 197 are correct and are factors of n.

Thanks for taking the time to read Let n 2 s times 39 times 52 times 197 Which of the following are factors of n a 13 b 39 c 52 d. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada