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Answer :
When Darin jumps out of the airplane, he experiences 118 N of air resistance. Taking into account his mass of 82.5 kg, his net force is calculated to be 690.5 N. With this net force, Darin's acceleration at that instant is approximately 8.37 m/s².
To determine Darin's acceleration at the instant he jumps out of the airplane, we need to consider the forces acting on him. The force of air resistance is given as 118 N, and we can assume that the gravitational force pulling him downwards is equal to his weight.
The force of gravity acting on Darin can be calculated using the formula F = m * g, where m is his mass (82.5 kg) and g is the acceleration due to gravity (approximately 9.8 m/s²). Therefore, the force of gravity is approximately 808.5 N.
To calculate the net force acting on Darin, we subtract the force of air resistance from the force of gravity: Net force = Force of gravity - Force of air resistance = 808.5 N - 118 N = 690.5 N.
Finally, we can determine Darin's acceleration using Newton's second law of motion,
F = m * a, where F is the net force and m is the mass. Rearranging the equation, we have a = F / m. Plugging in the values, we get a = 690.5 N / 82.5 kg ≈ 8.37 m/s².
Therefore, at the instant Darin jumps out of the airplane, his acceleration is approximately 8.37 m/s².
To learn more about gravitational force: https://brainly.com/question/29190673
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