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A 6 V battery maintains the electric potential difference between two parallel metal plates separated by 1 mm. What is the electric field between the plates?

Answer :

The electric field between the parallel metal plates is 6,000 V/m in a 6 v battery maintains the electric potential difference between two parallel metal plates separated by 1 mm.

This can be determined using the equation E=V/d, where E is the electric field, V is the potential difference (in volts), and d is the distance between the plates (in meters). In this case, V=6 V and d=0.001 m (or 1 mm), so E=6/0.001=6,000 V/m.
The electric field represents the force per unit charge experienced by a test charge placed in the field. In this case, the battery is maintaining a constant potential difference between the plates, creating a uniform electric field between them.

The distance between the plates determines the strength of the field, with a smaller distance resulting in a stronger field.
The electric field between the parallel metal plates is determined by the potential difference maintained by the 6 V battery and the distance between the plates. Using the equation E=V/d, we can calculate the electric field to be 6,000 V/m.

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