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If you cross a (w) white chicken with a (b) black chicken under incomplete dominance, what are the genotype ratios?

A. bb 25%, bw 50%, ww 25%
B. bb 0%, bw 100%, ww 0%
C. bb 50%, bw 0%, ww 50%
D. bb 75%, bw 25%, ww 0%

Answer :

Final answer:

In incomplete dominance, crossing heterozygotes produces offspring with intermediate phenotypes, resulting in a genotypic ratio of 1:2:1. Therefore, when crossing a white (ww) and a black (bb) chicken, all offspring will have the speckled phenotype (bw), Therefore, the option (B) bb 0%, bw 100%, ww 0% is the correct answer.

Explanation:

If you cross a white chicken (represented by allele w) with a black chicken (represented by allele b) and the trait exhibits incomplete dominance, you would expect to see a blending of these traits in their offspring. In this case, the white and black traits blend to produce offspring with an intermediate phenotype, such as speckled or grey chickens.

Incomplete dominance means that neither allele is completely dominant over the other. When you cross two chickens with heterozygous genotypes (Bw), you use a Punnett square to predict the ratios of the genotypes of the offspring. For the cross Bw x Bw, the expected genotypic ratio is 1 BB : 2 Bw : 1 ww, correlating to phenotype ratios of 1 black : 2 speckled : 1 white.

Looking at the provided options, the correct answer is b. bb 0%, bw 100%, ww 0%, meaning that all of the offspring will have the intermediate (speckled) phenotype, as this is a cross between two heterozygotes exhibiting incomplete dominance. Therefore, the option (B) bb 0%, bw 100%, ww 0% is the correct answer.

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