High School

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HT bisects SR at point H. If SH = [tex](x^2 + 6x - 28)[/tex] and HR = [tex](4x + 20)[/tex], find SR.

A) SR = [tex]x^2 + 10x - 8[/tex]
B) SR = [tex]5x^2 + 26x - 48[/tex]
C) SR = [tex]4x^2 + 26x - 8[/tex]
D) SR = [tex]x^2 + 26x + 20[/tex]
E) SR = [tex]4x^2 + 10x - 48[/tex]

Answer :

Final answer:

To find SR, add SH and HR to get SR = x² + 10x - 8.

Explanation:

To find SR, we need to add SH and HR. Thus, SR = SH + HR.

SR = (x² + 6x - 28) + (4x + 20)

SR = x² + 6x - 28 + 4x + 20

Combining like terms, SR = x² + 10x - 8

Therefore, the correct answer is A) SR = x² + 10x - 8.

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