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Answer :
To find the number of bromine atoms in 37.9 g of [tex]CH_2Br_2[/tex], calculate the molar mass of [tex]CH_2Br_2[/tex], determine the moles of the compound, and then multiply by two to find the number of bromine atoms.
The number of bromine atoms present in 37.9 g of [tex]CH_2Br_2[/tex] can be calculated by considering the molar mass of [tex]CH_2Br_2[/tex] and the molar mass of bromine.
First, calculate the molar mass of [tex]CH_2Br_2[/tex]:
- Carbon (C): 1 atom x 12.01 g/mol = 12.01 g/mol
- Hydrogen (H): 2 atoms x 1.01 g/mol = 2.02 g/mol
- Bromine (Br): 2 atoms x 79.904 g/mol = 159.808 g/mol
- Total molar mass of [tex]CH_2Br_2[/tex] = 12.01 + 2.02 + 159.808 = 173.838 g/mol
Next, calculate the number of moles of [tex]CH_2Br_2[/tex]in 37.9 g:
Moles = Mass / Molar mass = 37.9 g / 173.838 g/mol = 0.218 mol
Since there are 2 bromine atoms in each molecule of [tex]CH_2Br_2[/tex], multiply the number of moles by 2 to find the number of bromine atoms:
Number of Br atoms = 0.218 mol x 2 = 0.436 moles of Br atoms
Therefore, there are 0.436 moles of bromine atoms present in 37.9 g of [tex]CH_2Br_2[/tex].
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