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The A string on a violin has a fundamental frequency of 440 Hz. The length of the vibrating portion is 30.4 cm, and it has a mass of 0.342 g. Under what tension must the string be placed?

Answer :

Answer: The tension in the A string of the violin must be placed under 263.7 N of tension.

The A string on a violin has a fundamental frequency of a 440 Hz.

To find the tension (T) in a string: T = (m * v²) / L

Where: m = the mass of the string, L = the length of the vibrating portion, v = the speed of the wave. The speed of the wave is given by the formula: v = √(T/μ)

Where T is the tension in the string and μ is the linear density of the string. To calculate the linear density of the string, we use the formula: μ = m/L

Fundamental frequency, f = 440 Hz

Length of the vibrating portion, L = 30.4 cm = 0.304 m

Mass of the string, m = 0.342 g = 0.000342 kg.

Using the frequency and the length of the vibrating portion, we can find the speed of the wave:

v = f * λλ

= 2L = 2(0.304 m)

= 0.608 mv

= (440 Hz)(0.608 m)

= 267.52 m/s.

Now, we can find the tension in the string:

T = (m * v²) / L

T = (0.000342 kg * (267.52 m/s)²) / 0.304 m

T ≈ 263.7 N.

Therefore, the tension in the A string of the violin must be placed under 263.7 N of tension.

Learn more about tension: https://brainly.com/question/24994188

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