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Answer :
Answer:
The acceleration of the object is 314.57 m/[tex]s^{2}[/tex].
Explanation:
From Newton's second law of motion,
F = ma
where: F is the force applied on an object, m is the mass of the object and a is the acceleration of the object.
⇒ a = [tex]\frac{F}{m}[/tex]
In the given question, the resultant force, F should be determined.
Total horizontal force, [tex]F_{x}[/tex] = 16 - 126
= -110 N
The horizontal force applied to the object is 110 N to the left.
Vertical force, [tex]F_{y}[/tex] = 4 N.
Resultant force, F = [tex]\sqrt{F_{x} ^{2} + F_{y} ^{2} }[/tex]
= [tex]\sqrt{(-110)^{2} + (4)^{2} }[/tex]
= [tex]\sqrt{12116}[/tex]
= 110.0727
Resultant force, F = 110.1 N
So that,
a = [tex]\frac{110.1}{0.35}[/tex]
= 314.5714
a = 314.57 m/[tex]s^{2}[/tex]
The acceleration of the object is 314.57 m/[tex]s^{2}[/tex].
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Rewritten by : Barada
The object's acceleration with a mass of 0.35 kg, with a net force of 110 N acting to the left, is 314.29 m/s² to the left.
To calculate the acceleration of the object given the applied forces and mass, we need to use Newton's second law of motion, which states that the force, F, on an object is equal to its mass, m, multiplied by its acceleration, a (F = ma). In this case, we have opposing horizontal forces of 16 N to the right and 126 N to the left, and a vertical force of 4 N downward. First, we find the net force by subtracting the rightward force from the leftward force: 126 N (left) - 16 N (right) = 110 N (left). The vertical force does not affect the horizontal acceleration, so we can ignore it for this calculation part. Next, we use the object's mass (0.35 kg) to find the acceleration. According to Newton's second law, a = F/m. Therefore, the acceleration is 110 N / 0.35 kg, which is 314.29 m/s² to the left.
