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Answer :
Final answer:
The loop will be executed 101 times.
Explanation:
To determine the number of times the loop will be executed, we need to analyze the given code:
- Initialize the AX register to 0 using the 'MOV' instruction.
- Initialize the ECX register to 101 using the 'MOV' instruction.
- Start the loop labeled as L1.
- Increment the AX register by 1 using the 'Inc' instruction.
- Decrement the ECX register by 1 using the 'Loop' instruction and jump to L1 if ECX is not zero.
Since the initial value of ECX is 101, the loop will be executed 101 times. Each time the loop is executed, the AX register is incremented by 1. Therefore, the final value of AX will be 101.
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