We appreciate your visit to At what separation is the electrostatic force between a 12 6 C point charge and a 27 7 μC point charge equal in magnitude to. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Final answer:
The separation at which the electrostatic force between two point charges is equal to 1.64 N is approximately 0.84 meters by using Coulomb's law .
Explanation:
The electrostatic force between two point charges is given by Coulomb's law:
F = k * (|q1 * q2| / r^2)
Where F is the force, k is the Coulomb constant, q1 and q2 are the magnitudes of the charges, and r is the separation between the charges.
Given that the force magnitude is 1.64 N, q1 = 12.6 C, q2 = 27.7 xC, and they are equal, we can solve for r:
1.64 N = (9 x 10^9 N*m^2/C^2) * (12.6 C) * (27.7 x 10^-6 C) / r^2
Simplifying the equation and solving for r gives us:
r = sqrt((9 x 10^9 N*m^2/C^2) * (12.6 C) * (27.7 x 10^-6 C) / 1.64 N)
r = 0.84 meters
Learn more about Coulomb's law here:
https://brainly.com/question/506926
#SPJ11
Thanks for taking the time to read At what separation is the electrostatic force between a 12 6 C point charge and a 27 7 μC point charge equal in magnitude to. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
