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A, B and L are points on a circle, centre O.

AB is a chord of the circle.

M is the midpoint of AB.

LOM is a straight line.


AB = 24cm. LM = 18cm.


Calculate the diameter of the circle

A B and L are points on a circle centre O AB is a chord of the circle M is the midpoint of AB LOM

Answer :

Thus, the diameter of the circle for the given length of chord Ab is found as: 26 cm.

Explain about the diameter of circle?

Any line segment that traverses a circle's centre and has both of its endpoints here on circle itself is said to have a diameter of that circle.

Given data:

  • AB is a chord of the circle.
  • M is the midpoint of AB.
  • LOM forms straight line.
  • AB = 24cm.
  • LM = 18cm.

Let the radius of the circle be 'r'

In right triangle OMB.

OB² = OM² + MB²

r² = (18 - r)² + 12²

Further simplifying;

r² = (18)² + (r)² - 2*18*r + 12²

2*18*r = 324 + 144

r = 468 / 36

r = 13

Diameter = 2*13 = 26 cm

Thus, the diameter of the circle for the given length of chord Ab is found as: 26 cm.

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