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Answer :
Final answer:
The force of impact when a 65 kg dog running at 10 m/s crashes into a sliding glass door and stops in 0.08 seconds is 8125 N after calculating the change in momentum and dividing by the time of impact.
Explanation:
The question involves calculating the force of impact when a dog crashes into a sliding glass door. To find this force, we can use the formula F = Δp / Δt, where F is the force, Δp is the change in momentum, and Δt is the time over which the change occurs. The dog's momentum changes from m * v to 0 since the dog comes to a stop.
To calculate the change in momentum (Δp), we use the dog's mass (m = 65 kg) and initial velocity (v = 10 m/s). Thus, Δp = m * v = 65 kg * 10 m/s = 650 kg*m/s. The time (Δt) during which the impact occurs is 0.08s.
Now, we can find the force: F = Δp / Δt = 650 kg*m/s / 0.08 s = 8125 N. Therefore, the force of impact is 8125 N, which when rounded to the nearest whole number is 8125 N.
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