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Answer :
First, consider the overall reaction:
$$
Sr(OH)_2 + 2 HNO_3 \rightarrow Sr(NO_3)_2 + 2 H_2O
$$
Step 1: Identify the base.
- A base typically donates hydroxide ions ($OH^-$). In this reaction, the compound containing the hydroxide groups is $$Sr(OH)_2$$.
- Therefore, $$Sr(OH)_2$$ is the base.
Step 2: Identify the acid.
- An acid typically donates hydrogen ions ($H^+$). Here, the substance that provides these is $$HNO_3$$.
- Hence, $$HNO_3$$ is the acid.
Step 3: Identify the salt.
- A salt is formed from the reaction between an acid and a base by combining the positive ion of the base with the negative ion of the acid.
- In this reaction, $$Sr(NO_3)_2$$ is formed, making it the salt.
Step 4: Identify water.
- Water is produced as one of the products of the neutralization reaction.
- Here, $$H_2O$$ represents the water.
So, matching each compound with its role, we have:
- Base: $$Sr(OH)_2$$
- Acid: $$HNO_3$$
- Salt: $$Sr(NO_3)_2$$
- Water: $$H_2O$$
Thus, the correct mapping is:
$$\text{base} \rightarrow Sr(OH)_2, \quad \text{acid} \rightarrow HNO_3, \quad \text{salt} \rightarrow Sr(NO_3)_2, \quad \text{water} \rightarrow H_2O.$$
$$
Sr(OH)_2 + 2 HNO_3 \rightarrow Sr(NO_3)_2 + 2 H_2O
$$
Step 1: Identify the base.
- A base typically donates hydroxide ions ($OH^-$). In this reaction, the compound containing the hydroxide groups is $$Sr(OH)_2$$.
- Therefore, $$Sr(OH)_2$$ is the base.
Step 2: Identify the acid.
- An acid typically donates hydrogen ions ($H^+$). Here, the substance that provides these is $$HNO_3$$.
- Hence, $$HNO_3$$ is the acid.
Step 3: Identify the salt.
- A salt is formed from the reaction between an acid and a base by combining the positive ion of the base with the negative ion of the acid.
- In this reaction, $$Sr(NO_3)_2$$ is formed, making it the salt.
Step 4: Identify water.
- Water is produced as one of the products of the neutralization reaction.
- Here, $$H_2O$$ represents the water.
So, matching each compound with its role, we have:
- Base: $$Sr(OH)_2$$
- Acid: $$HNO_3$$
- Salt: $$Sr(NO_3)_2$$
- Water: $$H_2O$$
Thus, the correct mapping is:
$$\text{base} \rightarrow Sr(OH)_2, \quad \text{acid} \rightarrow HNO_3, \quad \text{salt} \rightarrow Sr(NO_3)_2, \quad \text{water} \rightarrow H_2O.$$
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