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Answer :
A bag contains 2 red checkers and 6 black checkers. a checker is selected, kept out of the bag, and then another checker is selected.
Total checkers = 2 red + 6 black = 8 checkers
p(black, then red)
Probability ( selecting checker) = [tex] \frac{numbe of selected checker }{total checkers} [/tex]
P( black) = [tex] \frac{6}{8} [/tex]
1 black is selected so remaining 7 checkers
P( red) = [tex] \frac{2}{7} [/tex]
p(black, then red) =[tex] \frac{6}{8} * \frac{2}{7} [/tex]
= [tex] \frac{12}{56} [/tex]
Divide numerator and denominator by 4
So P(black, then red) =[tex] \frac{3}{14} [/tex]
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