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Answer :
Final answer:
The volume of Kr under the given conditions is calculated using the ideal gas law equation. The number of moles is then converted into the equivalent weight in grams using the molar mass of Kr. The weight is approximately 104g of Kr.
Explanation:
This problem requires knowledge of the ideal gas law equation: PV = nRT; where P is pressure (atm), V is volume (L), n is the number of moles, R is the ideal gas constant (0.08206 L-atm/mol-K), and T is temperature in Kelvin. Therefore, we need to convert the temperature from Celsius to Kelvin. The conversion is T(K) = T(ºC) + 273.15. So, 98.3°C is equal to 371.45K and substituting the values into the equation, we get:
(9.40 atm * 1.78 L = n * 0.08206 L-atm/mol-K * 371.45 K).
Solving for n we get the number of moles of Kr which can be converted into grams using the molar mass of Kr (83.80 g/mol). The answer is approximately 104 g of Kr.
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