High School

We appreciate your visit to In a mixture weighing 155 kg three substances A B and C are in the ratio frac 1 2 frac 1 5 frac 1 3. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

In a mixture weighing 155 kg, three substances A, B, and C are in the ratio \(\frac{1}{2} : \frac{1}{5} : \frac{1}{3}\).

What is the quantity of substance A in the mixture?

A) 62 kg
B) 31 kg
C) 93 kg
D) 25 kg

Answer :

Final answer:

The mixture weighing 155 kg contains three substances A, B and C in the ratio 1/2:1/5:1/3. The quantity of substance A is 75 kg.

Explanation:

In the given question, a mixture weighing 155 kg contains three substances A, B and C. They are in the ratio 1/2:1/5:1/3. Our task is to calculate the quantity of substance A in the mixture. To solve this problem, we first calculate the total ratio of the mixture: 1/2 + 1/5 + 1/3 = 15/30 + 6/30 + 10/30 = 31/30. On simplifying the ratio by multiplying with 30, we get 15:6:10. Now, 15/31 corresponds with the ratio of A in the mixture.

Thus, the quantity of substance A in the mixture is 15/31 x 155 = 75 kg.

No option given corresponds to the correct value for the quantity of substance A in the mixture. Thus, none of the options are correct.

Learn more about Ratio and Proportion here:

https://brainly.com/question/26974513

#SPJ11

Thanks for taking the time to read In a mixture weighing 155 kg three substances A B and C are in the ratio frac 1 2 frac 1 5 frac 1 3. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada