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An attack helicopter is equipped with a 20-mm cannon that fires 197 g shells in the forward direction with a muzzle speed of 576 m/s. The fully loaded helicopter has a mass of 3980 kg. A burst of 187 shells is fired in a 5.01 s interval.

What is the resulting average force on the helicopter?

Answer in units of N.

Answer :

The resulting average force on the helicopter is 457,580.8 N.

What is the resulting average force on the helicopter?

The resulting average force on the helicopter is calculated by applying Newton's second law of motion as follows;

Mathematically, the formula for Newton's second law of motion is given as;

F = ma

where;

  • m is the total mass of the object
  • a is the acceleration of the object

F = ( mv / t )

where;

  • m is the total mass of the helicopter
  • v is the muzzle speed of the cannon
  • t is the time of interval in which the shell is fired

The resulting average force on the helicopter is calculated as follows;

F = ( 3980 x 576 ) / ( 5.01 )

F = 457,580.8 N

Thus, the resulting average force on the helicopter is a function of the mass of the helicopter, muzzle speed of the cannon and the time interval in which the shell was fired.

Learn more about average force here: https://brainly.com/question/16200276

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