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A field of 14.5-MeV neutrons deposits a kerma of 1.37 Gy at a point of interest in water. What is the fluence? (See Appendix F).

Answer :

The fluence of the field of 14.5-MeV neutrons is approximately 9.45 × 10⁸ neutrons/m².

The fluence is a measure of the number of particles passing through a unit area. To calculate the fluence, we need to convert the energy deposited (kerma) into the number of neutrons. From Appendix F, we can find the conversion factor that relates the kerma to the fluence for neutrons with a given energy. In this case, the kerma is given as 1.37 Gy. Using the appropriate conversion factor from the appendix, we can convert the kerma to fluence.

By dividing the kerma (in Gy) by the conversion factor (in Gy/neutron), we obtain the fluence in neutrons/m². Substituting the given values, we have 1.37 Gy / 14.5 MeV-neutron = (1.37 Gy) / (14.5 × 10⁶ eV-neutron) = 9.45 × 10⁸ neutrons/m².

Therefore, the fluence of the field of 14.5-MeV neutrons is approximately 9.45 × 10⁸ neutrons/m².

To know more about conversion factor refer here:

https://brainly.com/question/30567263#

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