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Answer :
Final answer:
To heat 140 kg of water from 24 °C to 100 °C, approximately 1,229 lb of oil are needed.
Explanation:
To calculate the amount of oil needed to heat water, we can use the equation:
Q = mcΔT
Where Q represents the heat energy, m represents the mass of the substance, c represents the specific heat capacity, and ΔT represents the change in temperature.
First, we need to calculate the heat energy required to raise the temperature of water from 24 °C to 100 °C. Assuming the specific heat capacity of water is 4.184 J/g °C:
Q = (140 kg) x (4.184 J/g °C) x (100 °C - 24 °C)
Q = 558,016 J
Next, we can convert the energy from joules to kilograms of oil using the conversion factor given. 1 lb = 454 g:
558,016 J x (1 lb / 454 g) = 1,229 lb
So, approximately 1,229 lb of oil are needed to heat 140 kg of water from 24 °C to 100 °C.
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