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Answer :
The three temperatures that mean all the same thing is option D) 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit.
To determine which temperature readings mean the same thing, we need to convert the temperatures from one scale to another. The three temperature scales in question are Kelvin (K), Celsius (°C), and Fahrenheit (°F).
1. Freezing Point of Water: 0 °C = 273.15 K = 32 °F
2. Boiling Point of Water: 100 °C = 373.15 K = 212 °F
3. Absolute Zero:0 K = -273.15 °C = -459.67 °F
Now we'll examine each option:
- Option A: 373 K, 100 °C, 273 °F
- 373 K is equivalent to 100 °C.
- 100 °C converted to Fahrenheit equals:
F = \left( \frac{9}{5} \times 100 \right) + 32 = 212 °F
- Thus, option A contains two temperatures that correspond to the boiling point of water and one that does not match (273 °F is not equivalent to 100 °C or 373 K). - Option B: 273 K, 100 °C, 212 °F
- 273 K is equivalent to 0 °C, not 100 °C.
- Therefore, this option is incorrect. - Option C: 100 K, 0 °C, 32 °F
- 100 K is equivalent to approximately 173.15 °C, not 0 °C, thus incorrect. - Option D: 273 K, 0 °C, 32 °F
- 273 K is indeed equivalent to 0 °C
- Also, 0 °C equals 32 °F.
- Thus, all three temperatures: 273 K, 0 °C, and 32 °F are equivalent.
After evaluating all options carefully, the correct choice is: D. 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit.
This choice confirms that all three temperature readings reflect the same thermal condition (the freezing point of water).
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Answer : The correct option is, (D) 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit
Explanation :
Conversion of degree Celsius to Kelvin :
[tex]K=^oC+273[/tex]
Conversion of degree Celsius to degrees Fahrenheit :
[tex]^oF=(\frac{9}{5}\times ^oC)+32[/tex]
By using these two conversion factors, we get the three temperature readings all mean the same thing.
For option A :
[tex]K=^oC+273=100+273=373K[/tex]
[tex]^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 100)+32=212^oF[/tex]
For option B :
[tex]K=^oC+273=100+273=373K[/tex]
[tex]^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 100)+32=212^oF[/tex]
For option C :
[tex]K=^oC+273=0+273=273K[/tex]
[tex]^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 0)+32=32^oF[/tex]
For option D :
[tex]K=^oC+273=0+273=273K[/tex]
[tex]^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 0)+32=32^oF[/tex]
From the given options, only option (D) is correct.
Hence, the correct option is, (D) 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit
