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Answer :
The volume occupied by 0.845 mol of nitrogen gas at a pressure of 1.37 atm and a temperature of 315 K is 16.8 L.
To calculate the volume occupied by 0.845 mol of nitrogen gas at a pressure of 1.37 atm and a temperature of 315 K, we can use the Ideal Gas Law equation:
PV = nRT
Where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
We can rearrange this equation to solve for V:
V = nRT/P
Now we can substitute the values we have:
V = (0.845 mol) x (0.0821 L•atm/mol•K) x (315 K) / (1.37 atm)
V = 16.8 L
Therefore, the volume occupied by 0.845 mol of nitrogen gas at a pressure of 1.37 atm and a temperature of 315 K is 16.8 L.
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