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1. There are three forces.
2. Yes, the forces on the beam are balanced.
3. The magnitude of the net force on them is zero.
4. The tension in Cable 1 is 8,596.49 N
5. The tension in Cable 2 is 8,596.49 N
The forces acting on the beam are two tension forces due to the cable and one gravitational pull due to its weight. Thus, there are three forces acting on the beam.
The force on the beam is perfectly balanced as the cable is uniformly attached to it. The beam is moving with constant velocity, thus the acceleration is zero, and hence, the net force acting on it is also zero.
The tension, T, in both cables is equal as they are inclined at the same angle.
Now, we resolve them into rectangular components and write
Tsin35 +Tsin35 = mg = 1000*9.8 = 9800
2Tsin35 = 9800
Tsin35 = 4900
T*0.57 = 4900
T = 8,596.49 N
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