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A weak base has [tex]K_B = 1.69 \times 10^{-3}[/tex]. What is the [tex]pK_B[/tex] of this base? Report your answer to at least 1 decimal place.

Answer :

Final answer:

To calculate the pKb of a weak base with a Kb of 1.69 x 10-3, use the formula pKb = -log(Kb). The pKb for this base is approximately 2.8.

Explanation:

The question requires us to find the pKb value for a given weak base with a known Kb. The pKb is calculated using the formula pKb = -log(Kb). Therefore, for a weak base with Kb = 1.69 x 10-3, the pKb calculation would be as follows:

pKb = -log(1.69 x 10-3)

By performing the calculation, we find that:

pKb ≈ 2.8

This result shows that the pKb of the weak base is approximately 2.8.

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Final answer:

The pKB of the given weak base is approximately 2.8.

Explanation:

To find the pKB of a weak base, we need to take the negative logarithm (base 10) of the given KB value. In this case, the given KB value is 1.69 x 10-3.

Using a calculator, we can calculate the pKB as follows:

  1. Take the negative logarithm (base 10) of the KB value:

pKB = -log10(KB)

Substituting the given KB value:

pKB = -log10(1.69 x 10-3)

Calculating this using a calculator, we get:

pKB ≈ 2.8

Learn more about calculating pkb of a weak base here:

https://brainly.com/question/33295032

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