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What is the domain of the function [tex]h(x) = \sqrt{x - 7} + 5[/tex]?

A. [tex]x \leq -7[/tex]

B. [tex]x \geq 7[/tex]

C. [tex]x \leq 5[/tex]

D. [tex]x \geq 5[/tex]

Answer :

To find the domain of the function [tex]\( h(x) = \sqrt{x - 7} + 5 \)[/tex], we need to consider the part of the function inside the square root, because a square root is only defined for non-negative numbers.

Here's how to determine the domain:

1. Identify the expression inside the square root: In the function [tex]\( h(x) = \sqrt{x - 7} + 5 \)[/tex], the expression inside the square root is [tex]\( x - 7 \)[/tex].

2. Set up an inequality for the expression inside the square root: Since square roots are only defined for non-negative values, we need:
[tex]\[
x - 7 \geq 0
\][/tex]

3. Solve the inequality: To find the values of [tex]\( x \)[/tex] that satisfy this inequality, solve for [tex]\( x \)[/tex]:
[tex]\[
x \geq 7
\][/tex]

4. Conclude the domain: The solution to the inequality tells us that [tex]\( x \)[/tex] can be any real number greater than or equal to 7. Therefore, the domain of the function [tex]\( h(x) \)[/tex] is:
[tex]\[
x \geq 7
\][/tex]

This means the correct answer is:

B. [tex]\( x \geq 7 \)[/tex]

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