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Answer :
The normal boiling point of CCl₄, calculated using the Clausius-Clapeyron equation, is approximately 76.5 °C.
The Clausius-Clapeyron equation can be used to find the normal boiling point of a substance. Since the normal boiling point is the temperature at which a substance boils at 1 atm pressure, we should set P₂ to 1 atm. However, our unit for pressure is given in kPa so we will use 101.3 kPa = 1 atm. Therefore, P₂ = 101.3 kPa. Since the equation is in the form In P₂/P₁ = -∆ᵥₐₚ/R (1/T₂-1/T₁), we will set the left side to In (101.3 kPa/54.0 kPa), ∆ᵥₐₚ to 33.05 kJ/mol (which should be converted to J/mol by multiplying by 1000), and T₁ to 57.8°C (which should be converted to K by adding 273), then solve for T₂. Using this equation, the normal boiling point of CCl₄ comes out to be approximately 76.5 °C.
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