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Answer :
Answer:
The 99% confidence interval estimate for the mean is 97.9576 ≤ μ ≤ 98.246
A) This suggests that the mean body temperature could very possibly be 98.6 °F
Step-by-step explanation:
The number of body temperatures, n = 103
The mean body temperature, [tex]\bar x[/tex] = 98.1
The standard deviation, s = 0.56
Confidence interval required = 99%
Confidence interval, CI is given by
[tex]CI=\bar{x}\pm z\frac{s}{\sqrt{n}}[/tex]
Plugging in the values we get;
z = 2.56 at 99%
[tex]CI=98.1}\pm 2.56\times \frac{0.56}{\sqrt{103}}[/tex]
Therefore, we have
[tex]\mu_{min} = 97.9579 , \ \mu_{max} = 98.242[/tex],
The statistical result suggest that at 99% confidence level, the sample mean temperature is likely to be 98.1 °F
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