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Answer :
a ) The final momentum of the car = 3120 N
b ) The final velocity of the car = 3120/m m / s
According to Newton's second law of motion,
F = pf - pi / t
F = Force
pf = Final momentum
pi = Initial momentum
t = Time
For the first 6 seconds,
F = 305 N
t = 6 s
pi = 0 ( Assuming the car is at rest initially )
305 = ( pf - 0 ) / 6
pf = 1830 N
For the next six seconds,
F = 215 N
t = 6 s
pi = 1830 N
215 = ( pf - 1830 ) / 6
1290 = pf - 1830
pf = 3120 N
In the final 6 seconds,
pf = 3120 N
m v = 3120 N
v = 3120 / m
Therefore,
a ) The final momentum of the car = 3120 N
b ) The final velocity of the car = 3120/m m / s
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