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Answer :
Final answer:
The charge that flows from a 12.0-volt battery when connected to a 9 μF capacitor is 1.08 x 10⁻´ coulombs.
Explanation:
The amount of charge (Q) that flows from a battery when it is connected to a capacitor can be found using the formula Q = CV, where C is the capacitance and V is the voltage. For a 12.0 volt battery connected to a 9 x 10⁻¹ Farad (9 μF) capacitor, the charge Q is calculated as:
Q = CV = (9 x 10⁻¹ F)(12.0 V) = 1.08 x 10⁻´ coulombs (C)
Therefore, the charge that flows is 1.08 x 10⁻´ C.
An electrical device with two terminals that may store energy as an electric charge is called a capacitor. It is made up of two electrical conductors spaced apart by a certain amount of distance. Vacuum can be used to fill the gap between the conductors, or a dielectric, an insulator, can be used instead.
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