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What is the value of the 30th term in the following arithmetic sequence: 12, 6, 0, -6, ...?

A. 186
B. -186
C. 342
D. -162

Answer :

Its -162 hope this helps you.

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Rewritten by : Barada

A sequence is said to be an arithmetic sequence if the difference between two consecutive terms remains constant thus the 30th term of the given series is -162.

What is Arithmetic progression?

The difference between every two successive terms in a sequence is the same this is known as an arithmetic progression (AP).

The arithmetic progression has wider use in mathematics for example sum of natural numbers.

As per the given arithmetic sequence,

12, 6, 0, -6, ... 186 -186 342 -162

First term a = 12

Common difference d = 6 - 12 = -6

The nth term is given as a + (n - 1)d

Thus, the 30th term will be,

12 + (30 - 1)(-6) = 12 = -162

Hence "A sequence is said to be an arithmetic sequence if the difference between two consecutive terms remains constant thus the 30th term of the given series is -162".

For more about Arithmetic progression,

https://brainly.com/question/20385181

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