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The acid ionization constant for [tex]\text{Cr(H}_2\text{O)}_6^{3+} (aq)[/tex] is [tex]1.0 \times 10^{-4}[/tex]. Calculate the pH of a [tex]0.0079 \, M[/tex] solution of [tex]\text{Cr(NO}_3)_3[/tex].

A. 4.00
B. 6.00
C. 8.00
D. 10.00

Answer :

Final answer:

The acid ionization constant for Cr(H2O)63+ is used to calculate the pH of a solution.

Explanation:

The acid ionization constant, also known as Ka, represents the extent to which an acid ionizes in water. In this case, the acid ionization constant for Cr(H2O)63+ is 1.0×10^-4. To calculate the pH of the solution, we need to determine the concentration of hydronium ions ([H3O+]). Once we have the concentration of hydronium ions, we can calculate the pH using the formula pH = -log[H3O+].

In this case, the concentration of Cr(H2O)63+ given is not the same as the concentration of hydronium ions. We need to find the concentration of hydronium ions using the acid ionization constant. We can set up an expression for the ionization of Cr(H2O)63+ and solve for [H3O+]. Once we have the concentration of hydronium ions, we can calculate the pH.

The correct answer is a) 4.00

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