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A block of mass 6.00 kg slides on a rough surface with a coefficient of kinetic friction of 0.300. What is the magnitude of the constant force applied to the block?

A. 45.0 N
B. 0.30 N
C. 6.00 N
D. 0.450 N

Answer :

Final answer:

To find the constant force applied to the block sliding on a rough surface, calculate the net force considering friction. The answer is option (a) 45.0 N.

Explanation:

To determine the magnitude of the constant force applied to a block of mass 6.00 kg with a coefficient of kinetic friction ( extmu) of 0.300, we use the equation for force due to friction: F_{fric} = extmu imes N, where N is the normal force. Considering the block is on a horizontal surface, the normal force is equal to the gravitational force on the block, so N = mg, where m is the mass and g is the acceleration due to gravity (9.8 m/s2).

The magnitude of the constant force applied to the block can be calculated using Newton's second law and taking into account the frictional force:

Sum of forces = mass x acceleration

20 N - (6.00 kg x 9.81 m/s^2 x 0.300) = 6.00 kg x acceleration

The constant force applied to the block is option (a) 45.0 N.

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