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A 145-gram baseball is typically hit with 4,000 pounds of force by professional baseball players. Calculate the acceleration of the baseball. Assume no air resistance.

Answer :

Final answer:

The acceleration of the baseball, when hit with 4000 pounds of force and has a weight of 145 grams, is approximately 55645.1353 m/s². This was calculated by converting the given force and weight to their SI equivalents and using Newton's second law (F = ma).

Explanation:

The problem is asking us to find the acceleration of a baseball that is hit with a certain amount of force. To solve this, we can use Newton's second law, F = ma, where F is force, m is mass, and a is acceleration.

However, there is a catch. The force given is in pounds, and the mass is in grams. We need to convert these units to their SI equivalents. There are approximately 0.00220462 pounds in a gram, so the mass of the baseball is 145 * 0.00220462 = 0.31967 kg. One pound of force is equivalent to 4.4482216 Newtons, so the force is 4000 * 4.4482216 = 17792.8864 N.

Substituting these values into F = ma, we have 17792.8864 = 0.31967 * a. Solving for a, we find that a = 17792.8864 / 0.31967 = 55645.1353 m/s².

Therefore, the acceleration of the baseball is approximately 55645.1353 m/s².

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