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Question 1

2 pts

A 93 kg person is skiing down a snowy hill, traveling at 9 m/s when they hit a 50 kg hiker on the skiing trail, who was standing still. The hiker ends

up moving backwards (in the direction the skier was moving) at 2 m/s after the collision. How fast, in m/s, will the skier be going right after the

collision? Enter your answer as just a number without units.

Question 1 2 pts A 93 kg person is skiing down a snowy hill traveling at 9 m s when they hit a 50 kg

Answer :

After the impact, the skier's speed will be 10.9 m/s.

What is conservation of momentum?

The total amount of momentum prior to and following the impact are equal.

(m1 + m2)vi = m1vf1 + m2vf2 {where m1 and m2 stand for the skier and hiker's respective masses, vi for the skier's starting velocity, and vf1 and vf2 for the skier and hiker's respective end velocities.}

(93 kg + 50 kg)(9 m/s) = 93 kg(vf1) + 50 kg(2 m/s)

Simplifying and solving for vf1, we get:

vf1 = (143 kg × 9 m/s - 50 kg × 2 m/s) / 93 kg = 10.9 m/s

What is momentum?

momentum is the result of a particle's mass and velocity. As a vector quantity, momentum possesses both magnitude and direction. According to Isaac Newton's second equation of motion, the force applied on a particle is equal to the time rate of change of momentum. Check out Newton's laws of motion.

To now more about Conservation of momentum

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