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Answer :
In wolves, coat color can be gray (g) or black (g), and eye color can be brown (b) or yellow (b). In this question, two wolves with the genotypes ggbb x ggbb mate. We are asked to determine the fraction of the pups that are predicted to be heterozygous for at least one of the two traits.
To solve this problem, we need to first determine the possible genotypes of the offspring. When two wolves with the genotypes ggbb x ggbb mate, each parent contributes one allele for each trait to their offspring.
Let's determine the possible genotypes for each trait separately.
For coat color:
- The genotype of the first parent is gg, and the genotype of the second parent is also gg.
- When two parents with the genotype gg mate, all of their offspring will have the genotype gg for coat color.
For eye color:
- The genotype of the first parent is bb, and the genotype of the second parent is also bb.
- When two parents with the genotype bb mate, all of their offspring will have the genotype bb for eye color.
Now, let's determine the fraction of pups that are predicted to be heterozygous for at least one of the two traits.
Since all the offspring will have the genotype gg for coat color and bb for eye color, none of them will be heterozygous for either trait.
Therefore, the fraction of the pups predicted to be heterozygous for at least one of the two traits is 0/1, which is 0.
So, none of the pups are predicted to be heterozygous for at least one of the two traits.
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