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Determine the estimated terminal velocity for a skydiver with the following parameters:

- Mass: 176 lb
- Fluid density of air near Earth's surface: 1.225 kg/m³
- Average frontal area: 1.0 m²
- Coefficient of drag: 0.5

Answer :

The terminal velocity of a skydiver with the given parameters is calculated using a specific Physics equation. After converting units appropriately, we find the terminal velocity to be approximately 160.6 km/h.

The subject of this question is Physics, specifically the study of fluid dynamics and motion. In Physics, terminal velocity is the maximum constant speed that a freely falling object eventually reaches when the resistance of the medium through which it is falling prevents further acceleration. It's given as Vt= √((2* mass *gravitational acceleration)/(fluid density * Area * drag coefficient)).

Let's start by converting the mass from pounds to kilograms, as the gravitational force is measured in N=kg.m/s². The skydiver with a mass of 176lb would be approximately 80 kg.

Now, we will plug in the known values into the formula: Vt = √((2*80 kg*9.81 m/s²)/(1.225 kg/m³ * 1.0 m² * 0.5)) = roughly 44.72 m/s or 160.6 km/h when rounded to two decimal places.

So, the estimated terminal velocity for a skydiver with a mass of 176lb, the fluid density of the air near earth’s surface being 1.225 kg/m³, the skydiver having an average frontal area of 1.0 m², and, in this instance, the coefficient of drag averaged out to be 0.5, is approximately 160.6 km/h.

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