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Answer :
Final answer:
The horizontal and vertical positions of a stone thrown horizontally from a cliff can be calculated using constant horizontal velocity and the free fall formula for the vertical position. The positions at 2-second intervals for the first 10 seconds have been calculated and provided. Therefore, The correct option is a:90.0,19.6, b:180.0:78.4, c:270.0:176.4, d: 360.0:313.6, e:450.0:490.0
Explanation:
For the horizontal position, we simply multiply the horizontal velocity (45.0 m/s) by the time elapsed. The vertical position is calculated using the formula for an object in free fall:
Vertical position = Initial vertical position + initial vertical velocity × time + ½ × acceleration due to gravity × time²
Since the initial vertical velocity is zero in the horizontal throw and the acceleration due to gravity (g) is approximately 9.81 m/s², we can calculate the positions at 2-second intervals. Initial vertical position is the height of the cliff and is considered zero here (assuming we're only calculating the displacement from the point of release).
- Horizontal position at 2.00 s: 90.0 meters, Vertical position at 2.00 s: 19.6 meters
- Horizontal position at 4.00 s: 180.0 meters, Vertical position at 4.00 s: 78.4 meters
- Horizontal position at 6.00 s: 270.0 meters, Vertical position at 6.00 s: 176.4 meters
- Horizontal position at 8.00 s: 360.0 meters, Vertical position at 8.00 s: 313.6 meters
- Horizontal position at 10.0 s: 450.0 meters, Vertical position at 10.0 s: 490.0 meters
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