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Answer :
In Line, E: y = 3x + 4 and Line F: y = [tex]\frac{-1}{3x} - 2[/tex] . Lines E and F are perpendicular because their slopes are negative reciprocals of each other. The slope of Line E is 3, while Line F has a slope of [tex]\frac{-1}{3}[/tex].
The option (C) is correct .
When you multiply these slopes, you get -1, which is the defining characteristic of perpendicular lines. Visually, this means that Line E goes upward at a steep angle, while Line F descends gently.
Perpendicular lines intersect at a [tex]90 \textdegree[/tex] angle. In this case, Line E and Line F form a right angle when they meet, confirming their perpendicular relationship. Line E has a slope of 3, and Line F has a slope of [tex]\frac{-1}{3}[/tex]. Their product is -1, so they are perpendicular.
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This question is not complete .Here i am attaching the complete question.
Which of the following pairs of lines are perpendicular?
A) Line A: y = 2x - 3 and Line B: y = -3x + 1
B) Line C: y = 4x + 2 and Line D: y = 2x - 1
C) Line E: y = 3x + 4 and Line F: y = [tex]\frac{-1}{3}[/tex] - 2
D) Line G: y = -4x + 5 and Line H: y = [tex]\frac{1}{4x}[/tex] - 6
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