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Answer :
Final answer:
Using Boyle's Law, the pressure of ethylene gas in a 25.0 L tank when it is initially at 200 L and four atm is calculated to be 32 atm.
Explanation:
To find the pressure of ethylene gas in a 25.0 L tank when the requirement is 200 L of gas at four atm, we assume ideal gas behavior and use Boyle's Law, which states that the product of pressure and volume is constant for a given mass of ideal gas at constant temperature (P1V1 = P2V2). We are given P1 (four atm), V1 (200 L), and V2 (25.0 L), and we need to solve for P2.
P1 × V1 = P2 × V2
(4 atm × 200 L) = P2 × 25.0 L
P2 = (4 atm × 200 L) / 25.0 L = 32 atm
So, the pressure of ethylene gas in the 25.0 L tank would be 32 atm, which corresponds to option C.
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