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Answer :
The price of one senior citizen ticket is $10, and the price of one child ticket is $8. Let's assume the price of one senior citizen ticket is "x" dollars and the price of one child ticket is "y" dollars.
1. On the first day, the school sold senior citizen tickets and child tickets for a total of $184. Since 12 child tickets were sold, the revenue from child tickets is 12 * y = 12y dollars. The remaining revenue, obtained from senior citizen tickets, is 184 - 12y dollars.
2. On the second day, the school sold 6 senior citizen tickets and 4 child tickets, generating a total revenue of $76. The revenue from senior citizen tickets is 6 * x = 6x dollars, and the revenue from child tickets is 4 * y = 4y dollars.
3. Combining the information from both days, we can form the following equations:
12y + 6x = 184 (equation 1)
4y + 6x = 76 (equation 2)
4. To solve this system of equations, we can multiply equation 2 by 3 to eliminate the term "6x":
12y + 18x = 228 (equation 3)
Subtracting equation 1 from equation 3, we get:
12y + 18x - 12y - 6x = 228 - 184
12x = 44
x = 44/12 = 11/3
Substituting the value of x back into equation 1:
12y + 6(11/3) = 184
12y + 22 = 184
12y = 184 - 22
12y = 162
y = 162/12 = 27/2 = 13.5
5. Therefore, the price of one senior citizen ticket is $11/3 or approximately $3.67, and the price of one child ticket is $13.5/2 or $6.75.
Learn more about equation here: brainly.com/question/29538993
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