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Use the following sample to estimate a population mean [tex]\mu[/tex]:

27.1, 34.8, 36.3, 15.1, 70.3, 39, 41.5, 13.6, 61.1, 40.3

Assuming the population has a bell-shaped distribution, find the 90% confidence interval about the population mean. Enter your answer as an open interval (i.e., parentheses) accurate to two decimal places.

90% C.I. = ______

Answer :

Final Answer:

The 90% confidence interval about the population mean is (28.88, 49.02).

Explanation:

To calculate the confidence interval for the population mean, we use the formula:

[tex]\[ \text{Confidence Interval} = \bar{x} \pm Z \cdot \frac{s}{\sqrt{n}} \][/tex]

Where:

- [tex]\(\bar{x}\)[/tex] is the sample mean,

- [tex]\(Z\)[/tex] is the critical value corresponding to the desired confidence level (for a 90% confidence level, [tex]\(Z \approx 1.645\))[/tex],

- [tex]\(s\)[/tex] is the sample standard deviation,

- [tex]\(n\)[/tex] is the sample size.

From the given sample, we have:

- Sample mean [tex](\(\bar{x}\))[/tex]: 34.13

- Sample standard deviation [tex](\(s\))[/tex]: 17.96

- Sample size [tex](\(n\))[/tex]: 10

Plugging in these values and the critical value, we get:

[tex]\[ \text{Confidence Interval} = 34.13 \pm 1.645 \cdot \frac{17.96}{\sqrt{10}} \][/tex]

Calculating this gives us a confidence interval of (28.88, 49.02), rounded to two decimal places.

This means that we can be 90% confident that the true population mean falls within the interval (28.88, 49.02).

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