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Answer :
Final Answer:
The 90% confidence interval about the population mean is (28.88, 49.02).
Explanation:
To calculate the confidence interval for the population mean, we use the formula:
[tex]\[ \text{Confidence Interval} = \bar{x} \pm Z \cdot \frac{s}{\sqrt{n}} \][/tex]
Where:
- [tex]\(\bar{x}\)[/tex] is the sample mean,
- [tex]\(Z\)[/tex] is the critical value corresponding to the desired confidence level (for a 90% confidence level, [tex]\(Z \approx 1.645\))[/tex],
- [tex]\(s\)[/tex] is the sample standard deviation,
- [tex]\(n\)[/tex] is the sample size.
From the given sample, we have:
- Sample mean [tex](\(\bar{x}\))[/tex]: 34.13
- Sample standard deviation [tex](\(s\))[/tex]: 17.96
- Sample size [tex](\(n\))[/tex]: 10
Plugging in these values and the critical value, we get:
[tex]\[ \text{Confidence Interval} = 34.13 \pm 1.645 \cdot \frac{17.96}{\sqrt{10}} \][/tex]
Calculating this gives us a confidence interval of (28.88, 49.02), rounded to two decimal places.
This means that we can be 90% confident that the true population mean falls within the interval (28.88, 49.02).
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