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A jetliner goes from rest to a takeoff speed of 178 mi/h in 36.3 seconds. What is the magnitude of its average acceleration in [tex] m/s^2 [/tex]?

Answer :

To find the magnitude of the average acceleration in m/s^2, we need to convert the given speed from miles per hour (mi/h) to meters per second (m/s).

First, let's convert 178 mi/h to m/s.

1 mile is approximately equal to 1.60934 kilometers (km), and 1 kilometer is equal to 1000 meters (m). So, we have:

178 mi/h * 1.60934 km/mi * 1000 m/km = 286.47 m/s

Next, we can use the formula for average acceleration:

average acceleration = (final velocity - initial velocity) / time

The initial velocity is 0 m/s (since the jetliner starts from rest), the final velocity is 286.47 m/s, and the time is 36.3 s.

average acceleration = (286.47 m/s - 0 m/s) / 36.3 s ≈ 7.89 m/s^2

Therefore, the magnitude of the average acceleration of the jetliner is approximately 7.89 m/s^2.

To learn more about magnitude click here: brainly.com/question/28714281

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