We appreciate your visit to The freezing temperatures for water on the Celsius and Fahrenheit scales are 0ºC and 32ºF respectively The boiling temperatures for water are 100ºC and 212ºF. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Answer:
Therefore the required function is
[tex]C= \frac{5}{9} (F-32)[/tex]
Therefore 25°C=57°F
Explanation:
F denotes temperature of Fahrenheit and C denotes temperature of Celsius.
[tex]\frac{C-0}{100-0} =\frac{F-32}{212-32}[/tex]
[tex]\Rightarrow C= \frac{100}{180} (F-32)[/tex]
[tex]\Rightarrow C= \frac{5}{9} (F-32)[/tex]
Therefore the required function is
[tex]C= \frac{5}{9} (F-32)[/tex]
Putting C=25°C in above equation
[tex]25=\frac{5}{9} (F-32)[/tex]
[tex]\Rightarrow 25 \times \frac{9}{5} = F-32[/tex]
⇒45 =F-32
⇒F=32+45
⇒F=57
Therefore 25°C=57°F
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The conversion function from Celsius to Fahrenheit is F = (C × 9/5) + 32. Using this, 25°C is converted to 77°F.
The subject of this question is temperature conversion between Celsius and Fahrenheit scales. To create a conversion function from Celsius to Fahrenheit, we use the relationship that a change of 1°C is equivalent to a change of 1.8°F. Since the freezing point of water is 0°C and 32°F, we can derive the following function for converting temperature from Celsius to Fahrenheit:
F = (C × 9/5) + 32.
Using this function, we can convert 25°C into Fahrenheit as follows:
- Multiply the Celsius temperature by 9/5: 25 × 9/5 = 45.
- Add 32 to the result: 45 + 32 = 77.
Therefore, 25°C is equal to 77°F.
