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Answer :
The pressure of the oxygen in the cylinder can be calculated using the ideal gas law PV = nRT. Therefore, the pressure of the oxygen in the cylinder will be 125 atm.
As we know that,
PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant and T is the temperature (assumed constant). We can also use the proportionality relationship between the initial and final pressures and volumes, P1V1 = P2V2.
Given:
V1 = 2500 L
P1 = 1.00 atm
V2 = 20.0 L
We can rearrange the proportionality equation to find P2:
P2 = P1 * V1/V2
So P2 = 1.00 atm * 2500 L / 20.0 L = 125 atm
Therefore, the pressure of the oxygen in the cylinder will be 125 atm.
It is important to note that compressing a gas to such high pressures is not safe and could cause the cylinder to explode. In practice, this process will be done in steps and in controlled conditions.
Learn more about ideal gas law here:
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