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Answer :
To calculate the number of calories of heat gained by the water, we can use the formula:
q = m × c × ΔT
where q is the heat gained by the water, m is the mass of the water, c is the specific heat of water, and ΔT is the change in temperature.
First, we need to calculate the mass of the water. We know that the volume of water is 99.3 mL, which is equivalent to 99.3 g (since the density of water is 1 g/mL).
Next, we can calculate the change in temperature of the water:
ΔT = 33.8°C - 17.0°C = 16.8°C
Finally, we can substitute these values into the formula and solve for q:
q = m × c × ΔT
q = 99.3 g × 1 cal/g°C × 16.8°C
q = 1670.04 cal
Therefore, the number of calories of heat gained by the water is approximately 1670.0 calories (rounded to the nearest 0.1 calorie).
q = m × c × ΔT
where q is the heat gained by the water, m is the mass of the water, c is the specific heat of water, and ΔT is the change in temperature.
First, we need to calculate the mass of the water. We know that the volume of water is 99.3 mL, which is equivalent to 99.3 g (since the density of water is 1 g/mL).
Next, we can calculate the change in temperature of the water:
ΔT = 33.8°C - 17.0°C = 16.8°C
Finally, we can substitute these values into the formula and solve for q:
q = m × c × ΔT
q = 99.3 g × 1 cal/g°C × 16.8°C
q = 1670.04 cal
Therefore, the number of calories of heat gained by the water is approximately 1670.0 calories (rounded to the nearest 0.1 calorie).
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