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Answer :
Answer:
90%
Step-by-step explanation:
Let's call the percentage of students that read Time magazine by P(T), and the percentage of students that read U.S News and World Report by P(U). So, we have that:
P(T) = 0.63
P(U) = 0.51
P(T and U) = 0.24
To find the percentage of students that read either the Time magazine or the U.S.News and World Report magazine (that is, P(T or U)), we can use this formula:
P(T or U) = P(T) + P(U) - P(T and U)
So, we have that:
P(T or U) = 0.63 + 0.51 - 0.24 = 0.90
So the probability is 90%
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Final answer:
The probability that a randomly selected student at Mill University reads either Time magazine or U.S. News and World Report magazine is 90%.
Explanation:
The student is interested in finding the probability that a Mill University student reads either Time magazine or U.S. News and World Report magazine.
To calculate this, we use the formula for the probability of either event A or B occurring (P(A ∪ B) = P(A) + P(B) - P(A ∩ B)), where P(A ∪ B) represents the probability of A or B happening, P(A) is the probability of A happening, P(B) the probability of B happening, and P(A ∩ B) the probability of both A and B happening.
Given that 63% of students read Time (P(Time) = 0.63), 51% read U.S. News (P(U.S. News) = 0.51), and 24% read both (P(Both) = 0.24), we calculate the probability of a student reading either magazine as P(Either) = P(Time) + P(U.S. News) - P(Both) = 0.63 + 0.51 - 0.24 = 0.90, or 90%.
